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Configuration = 111
cycles = (10 8 1 9 4)(7 5 2 6 3)

a = 1, b = 2, c = 6
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cycles = (10 8 5 2 7 4 1 9 3)(6)

a = 2, b = 7, c = 10
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cycles = (10 7 1 4 6)(9)(8 5 3)(2)

a = 1, b = 4, c = 7
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cycles = (10 7 3)(9)(8 2 6)(5)(4)(1)

a = 2, b = 6, c = 8
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cycles = (10 3 5)(9)(8)(7)(6)(4)(2)(1)